Differentiate clearly between thermal conduction,thermal convection,and thermal radiation.
(N/A) Thermal energy can be transferred through three distinct mechanisms:
$1$. Thermal Conduction: Heat transfer in solids where particles vibrate about their mean positions without net displacement. It does not require gravity and does not involve the formation of currents.
$2$. Thermal Convection: Heat transfer in fluids (liquids and gases) where particles physically move from one region to another,carrying thermal energy. This process requires gravity and leads to the formation of convection currents.
$3$. Thermal Radiation: Heat transfer in the form of electromagnetic waves (specifically infrared radiation). It does not require any material medium for propagation and can occur in a vacuum.
$1$. Thermal Conduction: Heat transfer in solids where particles vibrate about their mean positions without net displacement. It does not require gravity and does not involve the formation of currents.
$2$. Thermal Convection: Heat transfer in fluids (liquids and gases) where particles physically move from one region to another,carrying thermal energy. This process requires gravity and leads to the formation of convection currents.
$3$. Thermal Radiation: Heat transfer in the form of electromagnetic waves (specifically infrared radiation). It does not require any material medium for propagation and can occur in a vacuum.
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Similar Questions
Three rods of Copper,Brass,and Steel are welded together to form a $Y$ shaped structure. The area of cross-section of each rod is $4 \ cm^2$. The end of the copper rod is maintained at $100^\circ C$,whereas the ends of the brass and steel rods are kept at $0^\circ C$. The lengths of the copper,brass,and steel rods are $46 \ cm$,$13 \ cm$,and $12 \ cm$ respectively. The rods are thermally insulated from the surroundings except at the ends. The thermal conductivities of copper,brass,and steel are $0.92$,$0.26$,and $0.12 \ CGS$ units respectively. The rate of heat flow through the copper rod is ....... $cal \ s^{-1}$.
DifficultJEE MAIN 2014
View Solution$A$ heated body emits radiation which has maximum intensity at frequency $f_m$. If the temperature of the body is doubled,then:
Difficult
View Solution$A$ rod of length $L$ and uniform cross-sectional area has varying thermal conductivity which changes linearly from $2K$ at end $A$ to $K$ at the other end $B$. The ends $A$ and $B$ of the rod are maintained at constant temperatures $100^oC$ and $0^oC$, respectively. At steady state, the graph of temperature $T = T(x)$, where $x$ is the distance from end $A$, will be:
In Column-$I$,system surroundings and in Column-$II$ modes of heat transfer are given below. Match the following:
Column-$I$ Column-$II$ $(a)$ Cup of hot tea in room $(i)$ Forced convection $(b)$ Substance kept near fire $(ii)$ Natural convection $(iii)$ Conduction $(iv)$ Radiation
| Column-$I$ | Column-$II$ |
|---|---|
| $(a)$ Cup of hot tea in room | $(i)$ Forced convection |
| $(b)$ Substance kept near fire | $(ii)$ Natural convection |
| $(iii)$ Conduction | |
| $(iv)$ Radiation |
Medium
View SolutionFill in the blanks:
$(a)$ $0.49 \frac{\text{cal}}{\text{cm} \cdot \text{K} \cdot \text{s}} = \dots \frac{\text{J}}{\text{m} \cdot \text{K} \cdot \text{s}}$
$(b)$ If the rate of emission of heat of a substance is less than its rate of absorption,then its temperature $\dots$.
$(c)$ The rate of emission of heat of a substance is directly proportional to $\dots$ of temperature of it and surroundings.
$(a)$ $0.49 \frac{\text{cal}}{\text{cm} \cdot \text{K} \cdot \text{s}} = \dots \frac{\text{J}}{\text{m} \cdot \text{K} \cdot \text{s}}$
$(b)$ If the rate of emission of heat of a substance is less than its rate of absorption,then its temperature $\dots$.
$(c)$ The rate of emission of heat of a substance is directly proportional to $\dots$ of temperature of it and surroundings.
Medium
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